The electrostatic potential on the surface of uniformly charged spherical shell of radius R=10 ~cm is 120 V. The potential at the centre of shell, at a distance r=5 ~cm from centre, and at a distance r=15 ~cm from the

Correct answer: A. 120 ~V, 120 ~V, 80 ~V Potential inside shell is equal to potential on surface V_ in =V_ surface = kQ R =120 ~V at r= 15 ~cm V= kQ r =(120 × 10)/(15)=80 ~V

JEE Main 20253 AprilMorning Shift

Exam: JEE Main
Year: 2025
Date: 3 April
Shift: Morning Shift
Subject: Physics
Chapter: Electrostatics

JEE Main 2025 · 3 April · Morning Shift · Physics · Electrostatics

The electrostatic potential on the surface of uniformly charged...

The electrostatic potential on the surface of uniformly charged spherical shell of radius

\mathrm{R}=10 \mathrm{~cm}

is 120 V. The potential at the centre of shell, at a distance

\mathrm{r}=5 \mathrm{~cm}

from centre, and at a distance

\mathrm{r}=15 \mathrm{~cm}

from the centre of the shell respectively, are :

Options

A $120 \mathrm{~V}, 120 \mathrm{~V}, 80 \mathrm{~V}$
B $40 \mathrm{~V}, 40 \mathrm{~V}, 80 \mathrm{~V}$
C $0 \mathrm{~V}, 0 \mathrm{~V}, 80 \mathrm{~V}$
D $0 \mathrm{~V}, 120 \mathrm{~V}, 40 \mathrm{~V}$

Correct answer

A. $120 \mathrm{~V}, 120 \mathrm{~V}, 80 \mathrm{~V}$

Step-by-step solution

Potential inside shell is equal to potential on surface

\mathrm{V}_{\mathrm{in}}=\mathrm{V}_{\text{surface }}=\frac{\mathrm{kQ}}{\mathrm{R}}=120

\mathrm{~V}

<br/>at

\mathrm{r}=

\mathrm{~cm}

\mathrm{V}=\frac{\mathrm{kQ}}{\mathrm{r}}=\frac{120 \times 10}{15}=80

\mathrm{~V}

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