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JEE Main 20252 AprilMorning Shift
Exam
JEE Main
Year
2025
Date
2 April
Shift
Morning Shift
Subject
Physics
Chapter
Electrostatics

JEE Main 2025 · 2 April · Morning Shift · Physics · Electrostatics

A point charge +q is placed at the origin. A second point charge +9...

A point charge +q is placed at the origin. A second point charge +9 q is placed at (d,0,0)(\mathrm{d}, 0,0) in Cartesian coordinate system. The point in between them where the electric field vanishes is :A point charge +q is placed at the origin. A second point charge +9 q is placed at (d, 0,0) in Cartesian coordinate

Options

  1. A(4 d/3,0,0)(4 \mathrm{~d} / 3,0,0)
  2. B(d/4,0,0)(\mathrm{d} / 4,0,0)
  3. C(3 d/4,0,0)(3 \mathrm{~d} / 4,0,0)
  4. D(d/3,0,0)(\mathrm{d} / 3,0,0)

Correct answer

B. (d/4,0,0)(\mathrm{d} / 4,0,0)

Step-by-step solution

A point charge +q is placed at the origin. A second point charge +9 q is placed at (d, 0,0) in Cartesian coordinate
Let Ep=0\mathrm{E}_{\mathrm{p}}=0
<br/>∴kqx2=k9q( d−x)2⇒ d−xx=3⇒x=d4<br/>\begin{aligned}<br/>& \therefore \frac{\mathrm{kq}}{\mathrm{x}^2}=\frac{\mathrm{k} 9 \mathrm{q}}{(\mathrm{~d}-\mathrm{x})^2} \\ & \Rightarrow \frac{\mathrm{~d}-\mathrm{x}}{\mathrm{x}}=3 \Rightarrow \mathrm{x}=\frac{\mathrm{d}}{4}<br/>\end{aligned}
∴\therefore co-ordinate of P is (d4,0,0)\left(\frac{\mathrm{d}}{4}, 0,0\right)
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