Two identical conducting spheres P and S with charge Q on each, repel each other with a force 16 ~N . A third identical uncharged conducting sphere R is successively brought in contact with the two spheres. The new

Correct answer: B. 6 ~N aligned & F_ P S Q^2 & F_ P S =16 ~N aligned Now If P ~\&~ R are brought in contact then Now If S \& R are brought in contact then New force between P ~\&~ S is : aligned & F_ PS Q 2 × 3 Q 4 & ~F_ PS 3 Q^2 8 =(3)/(8) × 16=6 ~N aligned

JEE Main 20246 AprilEvening Shift

Exam: JEE Main
Year: 2024
Date: 6 April
Shift: Evening Shift
Subject: Physics
Chapter: Electrostatics

JEE Main 2024 · 6 April · Evening Shift · Physics · Electrostatics

Two identical conducting spheres P and S with charge Q on each,...

Two identical conducting spheres

P

and

S

with charge

Q

on each, repel each other with a force

16 \mathrm{~N}

. A third identical uncharged conducting sphere

R

is successively brought in contact with the two spheres. The new force of repulsion between

\mathrm{P}

and

\mathrm{S}

is :

Two identical conducting spheres P and S with charge Q on each, repel each other with a force 16 ~N . A third identical

Options

A $1 \mathrm{~N}$
B $6 \mathrm{~N}$
C $12 \mathrm{~N}$
D $4 \mathrm{~N}$

Correct answer

B. $6 \mathrm{~N}$

Step-by-step solution

\begin{aligned} & F_{P S} \propto Q^2 \\ & F_{P S}=16 \mathrm{~N} \end{aligned}

Now If

\mathrm{P} ~\&~ \mathrm{R}

are brought in contact then Two identical conducting spheres P and S with charge Q on each, repel each other with a force 16 ~N . A third identical

Now If

S \& R

are brought in contact then Two identical conducting spheres P and S with charge Q on each, repel each other with a force 16 ~N . A third identical

New force between

P ~\&~ S

is :

\begin{aligned} & \mathrm{F}_{\mathrm{PS}} \propto \frac{\mathrm{Q}}{2} \times \frac{3 \mathrm{Q}}{4} \\ & \mathrm{~F}_{\mathrm{PS}} \propto \frac{3 \mathrm{Q}^2}{8}=\frac{3}{8} \times 16=6 \mathrm{~N} \end{aligned}

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