JEE Main20241 Feb 2024Evening ShiftPhysicsElectrostaticsActual
C 1 and C 2 are two hollow concentric cubes enclosing charges 2 Q and 3 Q respectively as shown in figure. The ratio of electric flux passing through C 1 and C 2 is:
Options
- A2 : 5
- B5 : 2
- C2 : 3
- D3 : 2
Correct answer
A. 2 : 5
Step-by-step solution
Gauss's law states that the net flux of an electric field in a closed surface is directly proportional to the enclosed electric charge. Therefore, ϕ smaller cube = 2 Q ε 0 Since the smaller cube is inside the bigger cube, so total charge contained by the bigger cube will be 2 Q + 3 Q = 5 Q . ϕ bigger cube = 5 Q ε 0 Therefore, required ratio will be, ϕ smaller cube ϕ bigger cube = 2 5 .