JEE Main202431 Jan 2024Evening ShiftPhysicsElectrostaticsActual
Force between two point charges q 1 and q 2 placed in vacuum at r cm apart is F . Force between them when placed in a medium having dielectric K = 5 at r 5 cm apart will be:
Options
- AF 25
- B5 F
- CF 5
- D25 F
Correct answer
B. 5 F
Step-by-step solution
Using Coulomb's law, we can write: In air F = 1 4 π ε 0 q 1 q 2 r 2 In medium F ' = 1 4 π K ε 0 q 1 q 2 r ' 2 = 1 4 π 5 ε 0 25 q 1 q 2 r 2 = 5 F