As shown in the figure, a configuration of two equal point charges q 0 = + 2 μ C is placed on an inclined plane. Mass of each point charge is 20 g . Assume that there is no friction between charge and plane. For the system of two point charges to be in equilibrium (at rest) the height h = x × 10 - 3 m . The value of x is Take 1 4 π ε 0 = 9 × 10 9 N m 2 C - 2 , g = 10 m s - 2

Step-by-step solution

For the condition of equilibrium, the Coulomb force is equal to m g sin θ . Hence, k q 0 2 4 h 2 = ( m g sin θ ) ⇒ k q 0 2 4 h 2 = 20 × 10 - 3 × 10 × 1 2 ⇒ 9 × 10 9 × 4 × 10 − 12 4 h 2 = 20 × 10 - 3 × 10 × 1 2 ⇒ h = 9 100   m = 0 . 3   m = 300 × 10 - 3   m h 2 = 9 100 ⇒ h = 3 10 m = 0 .3 m = 300 × 10 − 3 m