Electric potential at a point P due to a point charge of 5 × 10 - 9 C is 50 V . The distance of P from the point charge is: (Assume, 1 4 π ε 0 = 9 × 10 9 N m 2 C - 2 )

Step-by-step solution

The electric potential for a point charge is given by V = Q 4 π ε 0 r The data given is V = 50   V Q = 5 × 10 - 9   C So, the distance of the point is r = 1 4 π ε 0 Q V ⇒ r = 9 × 10 9 × 5 × 10 - 9 50 ⇒ r = 0 . 9   m = 90   cm