Expression for an electric field is given by E → = 4000 x 2 i ^ V m - 1 . The electric flux through the cube of side 20 cm when placed in electric field (as shown in the figure) is ______ V cm .

Step-by-step solution

Electric flux is expressed as ϕ = E → · A → = E A cos θ , here, A is area of the surface and θ is the angle between the electric field lines and the normal to A . The flux will be only from DEFG surface as on the surface OABC field is zero and for rest of the surface, area vector is perpendicular to field. So, ϕ = E A = 4000 × ( 0 . 2 ) 2 × ( 0 . 2 ) 2   = 4000 × 16 × 10 - 4   V   m = 640   V   cm