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A spherically symmetric charge distribution is considered with charge density varying as ρ r = ρ 0 3 4 − r R for r ≤ R Zero for r > R Where, r r < R is the distance from the centre O (as shown in figure). The electric field at point P will be :

Options

  1. Aρ 0 r 4 ε 0 3 4 - r R
  2. Bρ 0 r 3 ε 0 3 4 - r R
  3. Cρ 0 r 4 ε 0 1 - r R
  4. Dρ 0 r 5 ε 0 1 - r R

Correct answer

C. ρ 0 r 4 ε 0 1 - r R

Step-by-step solution

According to Gauss's law, the electric flux through a closed surface area is equal to the charge inside the surface divided by ε 0 . ⇒ ∮ E · → d s → = Q in ε 0 ⇒ E 4 π r 2 = ∫ 0 r ρ 0 3 4 - r R 4 π r 2 d r ε 0 ⇒ E 4 π r 2 = ρ o 4 π ε o 3 4 r 3 3 - r 4 4 R ⇒ E = ρ o r 4 ε o 1 - r R

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