A 1   m long copper wire carries a current of 1   A . If the cross section of the wire is 2 . 0   mm 2 and the resistivity of copper is 1 . 7 × 10 - 8   Ω   m . The force experienced by moving electron in the wire is _____ × 10 - 23   N (Charge of electron = 1 . 6 × 10 - 19 C )

Step-by-step solution

Given here, length l = 1   m , current i = 1   A , area A = 2 × 10 - 6   m and resistivity ρ = 1 . 7 × 10 - 8   Ω   m . Resistance of wire is R = ρ l A = 1 . 7 × 10 - 8 × 1 2 × 10 - 5 = 1 . 7 2 × 10 - 2   Ω Now, electric field in the wire is E = ρ J , where, J = i A is current density. Thus, E = i ρ A = i R = 1 × 1 . 7 2 × 10 - 2   V   m - 1 Electric force in terms of electric field is given by F = q E Ther