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JEE Main 202229 JuneEvening Shift
Exam
JEE Main
Year
2022
Date
29 June
Shift
Evening Shift
Subject
Physics
Chapter
Electrostatics

JEE Main 2022 · 29 June · Evening Shift · Physics · Electrostatics

If the electric potential at any point (x, y, z)m in space is given...

If the electric potential at any point (x,y,z)m\left(x, y, z\right)m in space is given by V=3x2V = 3{x}^{2} volt. The electric field at the point (1,0,3)m\left(1, 0, 3\right)m will be :

Options

  1. A3Vm−13{Vm}^{- 1}, directed along positive xx-axis.
  2. B3Vm−13{Vm}^{- 1}, directed along negative xx-axis.
  3. C6Vm−16{Vm}^{- 1}, directed along negative xx-axis.
  4. D6Vm−16{Vm}^{- 1}, directed along positive xx-axis.

Correct answer

C. 6Vm−16{Vm}^{- 1}, directed along negative xx-axis.

Step-by-step solution

Electric potential V=3x2V = 3{x}^{2}

Electric potential and electric field are related as E=−dVdx=−6xE = - \dfrac{d V}{d x} = - 6x.

At the point \left(1, 0, 3\right)m,</p><p>, </p><p>⇒ E = - 6 \times 1 = - 6V{m}^{- 1}</p><p>Thus,electricfieldis</p><p>Thus, electric field is6V{m}^{- 1}alongnegativealong negativex ‐ axis.

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