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JEE Main202126 Aug 2021Evening ShiftPhysicsElectrostaticsActual

The two thin coaxial rings, each of radius a and having charges + Q and - Q respectively are separated by a distance of s . The potential difference between the centres of the two rings is :

Options

  1. AQ 2 π ε 0 1 a - 1 s 2 + a 2
  2. BQ 4 π ε 0 1 a - 1 s 2 + a 2
  3. CQ 4 π ε 0 1 a + 1 s 2 + a 2
  4. DQ 2 π ε 0 1 a + 1 s 2 + a 2

Correct answer

A. Q 2 π ε 0 1 a - 1 s 2 + a 2

Step-by-step solution

V 1 = K Q a + - K Q s 2 + a 2 V 2 = K Q s 2 + a 2 + - K Q a V 1 - V 2 = Q 2 π ε 0 1 a - 1 s 2 + a 2

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