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A particle of mass 1 mg and charge q is lying at the mid-point of two stationary particles kept at a distance 2 m when each is carrying same charge q . If the free charged particle is displaced from its equilibrium position through distance x x < < 1 m . The particle executes SHM. Its angular frequency of oscillation will be _______ × 10 5 rad s - 1 (if q 2 = 10 C 2 )

Correct answer

0

Step-by-step solution

Net force on free charged particle, F = k q 2 d + x 2 - k q 2 d - x 2 F = - k q 2 4 d x d 2 - x 2 2 a = - 4 k q 2 d m x d 4 a = - 4 k q 2 m d 3 x So, angular frequency ω = 4   k q 2 m d 3 ω = 4 × 9 × 10 9 × 10 1 × 10 - 6 × 1 3 ω = 6 × 10 8   rad   sec - 1

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