JEE Main202117 Mar 2021Evening ShiftPhysicsElectrostaticsActual
The electric field in a region is given by E → = 2 5 E 0 i ^ + 3 5 E 0 j ^ with E 0 = 4 . 0 × 10 3 N C - 1 . The flux of this field through a rectangular surface, area 0 . 4 m 2 parallel to the Y - Z plane is _______ N m 2 C - 1 .
Correct answer
0
Step-by-step solution
ϕ = E x A ⇒ 2 5 × 4 × 10 3 × 0 . 4 = 640   N   m 2   C - 1