JEE Main202125 Feb 2021Evening ShiftPhysicsElectrostaticsActual
A charge q is placed at one corner of a cube as shown in figure. The flux of electrostatic field E → through the shaded area is:
Options
- Aq 8 ε 0
- Bq 24 ε 0
- Cq 48 ε 0
- Dq 4 ε 0
Correct answer
B. q 24 ε 0
Step-by-step solution
flux through cube = q 8 ϵ 0 flux through surfaces A B E H , A D G H , A B C D will be zero ϕ E F G H = ϕ D C F G = ϕ E B C F = 1 3 q 8 ϵ 0 = q 24 ϵ 0