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JEE Main202125 Feb 2021Evening ShiftPhysicsElectrostaticsActual

The peak electric field produced by the radiation coming from the 8 W bulb at a distance of 10 m is x 10 μ 0 c π V m - 1 . The efficiency of the bulb is 10 % and it is a point source. The value of x is,

Correct answer

0

Step-by-step solution

I = 1 2 c ε E 0 2 0 8 4 π × 10 2 × 1 2 = 1 4 × c × 1 μ 0 c 2 × E 0 2 E 0 = 2 10 × μ 0 c π ⇒ x = 2

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