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JEE Main20206 Sep 2020Morning ShiftPhysicsElectrostaticsActual

Charges Q 1 and Q 2 are at points A and B of a right-angled triangle O A B . The resultant electric field at point O is perpendicular to the hypotenuse, then Q 1 / Q 2 is proportional to:

Options

  1. Ax 1 3 x 2 3
  2. Bx 2 x 1
  3. Cx 1 x 2
  4. Dx 2 2 x 1 2

Correct answer

C. x 1 x 2

Step-by-step solution

Using triangle properties tan θ = x 1 x 2 tan θ = E 2 E 1 = K Q 2 / x 2 2 K Q 1 / x 1 2 ⇒ x 1 x 2 = K Q 2 / x 2 2 K Q 1 / x 1 2 Q 1 Q 2 = x 1 x 2

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