JEE Main20209 Jan 2020Morning ShiftPhysicsElectrostaticsActual
An electric dipole of moment p → = - i ^ - 3 j ^ + 2 k ^ × 10 - 29 C m at the origin 0,0 , 0 . The electric field due to this dipole at r → = + i ^ + 3 j ^ + 5 k ^ (note that r → ∙ p → = 0 ) is parallel to:
Options
- A+ i ^ - 3 j ^ - 2 k ^
- B- i ^ + 3 j ^ - 2 k ^
- C+ i ^ + 3 j ^ - 2 k ^
- D- i ^ - 3 j ^ + 2 k ^
Correct answer
C. + i ^ + 3 j ^ - 2 k ^
Step-by-step solution
As r → · p → = 0 , this means that r → is perpendicular to p → . For an electric dipole, electric field at equatorial position is antiparallel to p → . ⇒ E → = - λ p → , where, λ is an arbitrary positive constant. ⇒ E → = - λ - i ^ - 3 j ^ + 2 k ^ × 10 - 29   C   m - 2 ⇒ E → = λ i ^ + 3 j ^ - 2 k ^ × 10 - 29   C   m - 2 For λ = 1 10 - 29 ⇒ E → = i ^ + 3 j ^ - 2 k ^   C