Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
JEE Main201912 Apr 2019Evening ShiftPhysicsElectrostaticsActual

Let a total charge 2 Q be distributed in a sphere of radius R , with the charge density given by ρ ( r ) = k r , where r is the distance from the centre. Two charges A and B , of - Q each, are placed on diametrically opposite points, at equal distance, a, from the centre. If A and B do not experience any force, then:

Options

  1. Aa = 3 R 2 1 4
  2. Ba = R 3
  3. Ca = 2 - 1 4 R
  4. Da = 8 - 1 4 R

Correct answer

D. a = 8 - 1 4 R

Step-by-step solution

As total charge on sphere is = 2 Q 2 Q = ∫ 0 R k r 4 π r 2 d r ⇒ k πr 4 = 2 Q Charged enclosed in the sphere of radius   a q = ∫ 0 a k r × 4 π r 2 d r = k π a 4 As force on   Q   is zero 1 4 π ε 0 × Q 2 2 a 2 = k π a 4 4 π ε 0 × a 2 × Q ⇒ Q 2 4 = k π a 4 Q = a 4 2 Q R 4 Q R 4 = 8 a 4 ⇒ R = 8 1 4   a or   a = 8 - 1 4 R

Practice Electrostatics on Quantrex Academy →

More from Electrostatics

Two charges Q₁ = q and Q₂ = mq are placed at the points P₁(a, b) and P₂(ma, mb) , respectively, in the XY plane, where a, b 0 and m 0, 1 . If V₁ is the potential at a point in the 2026Consider an electric dipole comprising two charges +q and -q each with mass m , separated by a fixed distance d and initially at rest with its dipole moment pointing along i . A un 2026Two point charges q₁=3 , C and q₂=-4 , C are placed at points (2 i +3 j +3 k ) and ( i + j + k ) respectively. Force on charge q₂ is ________ N. ( Take 1 4 ₀ = 9 10^9 SI Units ) 2026The electric potential as a function of x, y is given by V = 5(x^2 - y^2) V. The electric field at a point (2, 3) m is __________ V/m. 2026A thin half ring of radius 35 cm is uniformly charged with a total charge of Q coulomb. If the magnitude of the electric field at centre of the half ring is 100 V/m, then the value 2026A three coulomb charge moves from the point (0, -2, -5) to the point (5, 1, 2) in an electric field expressed as E = 2x i + 3y^2 j + 4 k N/C. The work done in moving the charge is 2026A particle of charge q and mass m is projected from origin with an initial velocity v = ( v₀ 2 x + v₀ 2 y ) . There exists a uniform magnetic field B = B₀ z and a space varying ele 2026A rigid dipole undergoes a simple harmonic motion about its centre in the presence of an electric field E ₁=E₀ x . If another electric field E ₂=2E₀( y + z ) is introduced to the s 2026 Full Electrostatics list All JEE Main PYQs