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JEE Main20198 Apr 2019Morning ShiftPhysicsElectrostaticsActual

A solid conducting sphere, having a charge Q , is surrounded by an uncharged conducting hollow spherical shell. Let the potential difference between the surface of the solid sphere and that of the outer surface of the hollow shell be V . If the shell is now given a charge of – 4 Q , the new potential difference between the same two surfaces is:

Options

  1. A– 2 V
  2. B2 V
  3. CV
  4. D4 V

Correct answer

C. V

Step-by-step solution

First condition: Both conducting spheres are shown. V i n - V o u t = K Q r 1 - K Q r 2 ⇒ V = K Q 1 r 1 - 1 r 2 Second condition: Shell is now given charge - 4 Q . V i n - V o u t = K Q r 1 - 4 K Q r 2 - K Q r 2 - 4 K Q r 2 = K Q r 1 - K Q r 2 = K Q 1 r 1 - 1 r 2 = V

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