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JEE Main201912 Jan 2019Evening ShiftPhysicsElectrostaticsActual

A parallel plate capacitor with plates of area 1 m 2 each, are at a separation of 0.1 m . If the electric field between the plates is 100     N / C , the magnitude of charge on each plate is: ( Take     ∈ 0 = 8.85 × 10 − 12 C 2 N - m 2 )

Options

  1. A8.85 x 10 - 10 C
  2. B6.85 x 10 - 10 C
  3. C9.85 x 10 - 10 C
  4. D7.85 x 10 - 10 C

Correct answer

A. 8.85 x 10 - 10 C

Step-by-step solution

E = σ ε 0 = Q A ε 0 = 100 V / m Q = 100 × A ε 0 ⇒ Q = 100 × 1 × 8.85 × 10 - 12 C = 8.85 × 10 - 10 C

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