JEE Main201911 Jan 2019Evening ShiftPhysicsElectrostaticsActual
An electric field of 1000 ~V / m is applied to an electric dipole at angle of 45^ . The value of electric dipole moment is 10⁻²⁹ C m . What is the potential energy of the electric dipole?
Options
- A-20 10⁻¹⁸ ~J
- B-7 10⁻²⁷ ~J
- C-10 10⁻²⁹ ~J
- D-9 10⁻²⁰ ~J
Correct answer
B. -7 10⁻²⁷ ~J
Step-by-step solution
Potential energy of a dipole is given by U =- P E =-P E [Where = angle between dipole and perpendicular to the field =- (10⁻²⁹ ) (10³ ) 45^ =-0.707 10⁻²⁶ ~J =-7 10⁻²⁷ ~J