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Four closed surfaces and corresponding charge distributions are shown below. Let the respective electric fluxes through the surfaces be ϕ 1 , ϕ 2 , ϕ 3 and ϕ 4 . Then:

Options

  1. Aϕ 1 > ϕ 2 > ϕ 3 > ϕ 4
  2. Bϕ 1 < ϕ 2 = ϕ 3 > ϕ 4
  3. Cϕ 1 > ϕ 3 ; ϕ 2 < ϕ 4
  4. Dϕ 1 = ϕ 2 = ϕ 3 = ϕ 4

Correct answer

D. ϕ 1 = ϕ 2 = ϕ 3 = ϕ 4

Step-by-step solution

By Gauss law, &#160; &#981; = &#160; &#8721; q enclosed &#1013; o &#8721; q enclosed is same in all cases. &rArr; &#981; will be same in all four cases

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