JEE Main2014PhysicsElectrostaticsActual
The electric field in a region of space is given by, E → = E 0 i ^ + 2 E 0 j ^ where E 0 = 100 N C - 1 . The flux of this field through a circular surface of radius 0 . 02 m parallel to the Y ‐ Z plane is nearly
Options
- A0 . 02   N   m 2   C - 1
- B0 . 005   N   m 2   C - 1
- C0 . 125   N   m 2   C - 1
- D3 . 14   N   m 2   C - 1
Correct answer
C. 0 . 125   N   m 2   C - 1
Step-by-step solution
ϕ = E → · A → = E 0 i ^ + 2 E 0 j ^ · π r 2 i ^ = E 0 π r 2 = 0 . 125   N   m 2   C - 1