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The potential at a point x (measured in m ) due to some charges situated on the x -axis is given by V(x)=20 / (x^2-4 ) ~Volts . The electric field E at x=4 ~ m is given by

Options

  1. A5 / 3 ~Volt / m and in the -vex direction
  2. B5 / 3 ~Volt / m and in the +vex direction.
  3. C10 / 9 ~Volt / m and in the -vex direction
  4. D10 / 9 ~Volt / m and in the +vex direction.

Correct answer

D. 10 / 9 ~Volt / m and in the +vex direction.

Step-by-step solution

V_x= 20 x^2-4 E=- d V d x = 20 (x^2-4 )^2 (2 x-0)= 160 144 = 10 9

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