JEE Main2005PhysicsElectrostaticsActual
Two thin wires rings each having a radius R are placed at a distance d apart with their axes coinciding. The charges on the two rings are +q and -q . The potential difference between the centres of the two rings is
Options
- AQR / 4 ₀ ~d ^2
- BQ 2 ₀ [ 1 R - 1 R^2+d^2 ]
- Czero
- DQ 4 ₀ [ 1 R - 1 R^2+d^2 ]
Correct answer
B. Q 2 ₀ [ 1 R - 1 R^2+d^2 ]
Step-by-step solution
v₁= k q R - k q R^2+d^2 v₂= -k q R + k q R^2+d^2