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A thin spherical conducting shell of radius R has a charge q . Another charge Q is placed at the centre of the shell. The electrostatic potential at a point P a distance R 2 from the centre of the shell is

Options

  1. A2 Q 4 ₀ R
  2. B2 Q 4 ₀ R - 2 q 4 ₀ R
  3. C2 Q 4 ₀ R + q 4 ₀ R
  4. D( q + Q ) 2 4 ₀ R

Correct answer

C. 2 Q 4 ₀ R + q 4 ₀ R

Step-by-step solution

Potential due to spherical shell, v ₁= q 4 ₀ R . Potential difference due to charge at the centre V ₂= 2 Q 4 ₀ r ; V = V ₁+ V ₂= 2 Q 4 ₀ R + q 4 ₀ R

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