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JEE Main 202310 AprilMorning Shift
Exam
JEE Main
Year
2023
Date
10 April
Shift
Morning Shift
Subject
Physics
Chapter
Gravitation

JEE Main 2023 · 10 April · Morning Shift · Physics · Gravitation

Assuming the earth to be a sphere of uniform mass density, the...

Assuming the earth to be a sphere of uniform mass density, the weight of a body at a depth d=R2d = \dfrac{R}{2} from the surface of earth, if its weight on the surface of earth is 200N200N, will be : (Given R=R = radius of earth)

Options

  1. A300N300N
  2. B100N100N
  3. C400N400N
  4. D500N500N

Correct answer

B. 100N100N

Step-by-step solution

The acceleration due to gravity with depth is

g′=g(1−dR){g}^{'} = g\left(1 - \dfrac{d}{R}\right)

The given data is

W=200Nd=R2W = 200Nd = \dfrac{R}{2}

Let the weight be at the given depth, W′W '. Hence, the value is

mg′=mg(1−R2R)=m(g2)m{g}^{'} = mg\left(1 - \dfrac{\dfrac{R}{2}}{R}\right) = m\left(\dfrac{g}{2}\right)

The Weight W′W ' =W2=2002=100N= \dfrac{W}{2} = \dfrac{200}{2} = 100N

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