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JEE Main 20236 AprilMorning Shift
Exam
JEE Main
Year
2023
Date
6 April
Shift
Morning Shift
Subject
Physics
Chapter
Gravitation

JEE Main 2023 · 6 April · Morning Shift · Physics · Gravitation

A planet has double the mass of the earth. Its average density is...

A planet has double the mass of the earth. Its average density is equal to that of the earth. An object weighing WW on earth will weigh on that planet:

Options

  1. A214W2\dfrac{1}{4}W
  2. B213W2\dfrac{1}{3}W
  3. C2W2W
  4. D223W2\dfrac{2}{3}W

Correct answer

B. 213W2\dfrac{1}{3}W

Step-by-step solution

The formula for acceleration due to gravity is

g=GMR2g = \dfrac{GM}{{R}^{2}}

Let the density of earth and planet be ρρ, and the radius of the planet be R′R '. Let RR be the radius of the earth and gg be the acceleration due to gravity of earth and g′g ' be the acceleration due to gravity of planet.

So, the masses are

M=43πR3ρ...(i)M = \dfrac{4}{3}\pi{R}^{3}ρ . . . ( i )

M′=43π(R′)3ρ...(ii)M ' = \dfrac{4}{3}\pi{\left(R '\right)}^{3}ρ . . . ( ii )

So, g′g=GM′R′2GMR2=M′M(RR′)2...(iii)\dfrac{g '}{{g}^{}} = \dfrac{\dfrac{GM '}{R{'}^{2}}}{\dfrac{GM}{{R}^{2}}} = \dfrac{M '}{M}{\left(\dfrac{R}{R '}\right)}^{2} . . . ( iii )

From equation (i) and (ii) we get R′=213RR ' = 2\dfrac{1}{3}R

Substituting the value in equation (iii),

g′g=(21)2−23=213g\dfrac{g '}{g} = \left({2}^{1}\right)2\dfrac{- 2}{3} = 2\dfrac{1}{3}g

Weight is given by W′=mg′=213WW ' = mg ' = 2\dfrac{1}{3}W

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