If the acceleration due to gravity experienced by a point mass at a...

Acceleration due to gravity at a height $h$ above the earth's surface is given by $g$\left(1 - \dfrac{2h}{{R}_{e}}\right)$</p><p>And acceleration due to gravity at depth$d$below the earth surface is given by$g\left(1 - \dfrac{d}{{R}_{e}}\right)$.</p><p>As${g}_{above} = {g}_{below}$</p><p>So,$g\left(1 - \dfrac{2h}{{R}_{e}}\right) = g\left(1 - \dfrac{d}{{R}_{e}}\right)$</p><p>$⇒ \dfrac{2h}{{R}_{e}} = \dfrac{d}{{R}_{e}}$</p><p>$⇒ \alphah = d$</p><p>Thus, the value of$\alpha = 2.