The percentage decrease in the weight of a rocket, when taken to a...

Acceleration due to gravity at a height $h < < R$ is

${g}^{'} = g\left(1 - \dfrac{2h}{R}\right)$

Now, change in $g$ is

$∴ \dfrac{\Deltag}{g} = \dfrac{2h}{R}$

Percentage change is

$⇒ \dfrac{\Deltag}{g} \times 100 = \dfrac{2h}{R} \times 100$

$= 2 \times \dfrac{32}{6400} \times 100 = 1$