JEE Main202225 Jul 2022Evening ShiftPhysicsGravitationActual
An object is taken to a height above the surface of earth at a distance 5 4 R from the centre of the earth. Where radius of earth, R = 6400 km . The percentage decrease in the weight of the object will be
Options
- A36 %
- B50 %
- C64 %
- D25 %
Correct answer
A. 36 %
Step-by-step solution
Acceleration due to gravity at height h is given by, g ' = g 1 + h R 2 For distance from the centre r = 5 4 R height h = R 4 , ⇒ g ' = g 1 + 1 4 2 = 16 25 g Change in weight ∆ W = m g - m g ' ⇒ ∆ W = m g 1 - 16 25 ⇒ ∆ W = 9 25 m g Percentage change = 9 25 × 100 % = 36 %