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JEE Main 202229 JuneMorning Shift
Exam
JEE Main
Year
2022
Date
29 June
Shift
Morning Shift
Subject
Physics
Chapter
Gravitation

JEE Main 2022 · 29 June · Morning Shift · Physics · Gravitation

The escape velocity of a body on a planet A is 12km s ^ - 1 . The...

The escape velocity of a body on a planet AA is 12kms−112km{s}^{- 1}. The escape velocity of the body on another planet BB, whose density is four times and radius is half of the planet AA, is

Options

  1. A12kms−112km{s}^{- 1}
  2. B24kms−124km{s}^{- 1}
  3. C36kms−136km{s}^{- 1}
  4. D6kms−16km{s}^{- 1}

Correct answer

A. 12kms−112km{s}^{- 1}

Step-by-step solution

We know that escape velocity is given by,

v=2GMR⇒vAvB=MAMB×RBRA=ρARA3ρBRB3×RBRA=ρARA2ρBRB2=14×41⇒vB=vA=12kms−1v = \sqrt{\dfrac{2GM}{R}} ⇒ \dfrac{{v}_{A}}{{v}_{B}} = \sqrt{\dfrac{{M}_{A}}{{M}_{B}} \times \dfrac{{R}_{B}}{{R}_{A}}} = \sqrt{\dfrac{{ρ}_{A}{{R}_{A}}^{3}}{{ρ}_{B}{{R}_{B}}^{3}} \times \dfrac{{R}_{B}}{{R}_{A}}} = \sqrt{\dfrac{{ρ}_{A}{{R}_{A}}^{2}}{{ρ}_{B}{{R}_{B}}^{2}}} = \sqrt{\dfrac{1}{4} \times \dfrac{4}{1}} ⇒ {v}_{B} = {v}_{A} = 12km{s}^{- 1}

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