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JEE Main 202225 JuneMorning Shift
Exam
JEE Main
Year
2022
Date
25 June
Shift
Morning Shift
Subject
Physics
Chapter
Gravitation

JEE Main 2022 · 25 June · Morning Shift · Physics · Gravitation

The height of any point P above the surface of earth is equal to...

The height of any point PP above the surface of earth is equal to diameter of earth. The value of acceleration due to gravity at point PP will be : (Given g=g =acceleration due to gravity at the surface of earth).

Options

  1. Ag2\dfrac{g}{2}
  2. Bg4\dfrac{g}{4}
  3. Cg3\dfrac{g}{3}
  4. Dg9\dfrac{g}{9}

Correct answer

D. g9\dfrac{g}{9}

Step-by-step solution

Acceleration due to gravity at a height hh from the surface of the Earth,
g′=g1(1+hR)2{g}^{'} = g\dfrac{1}{{\left(1 + \dfrac{h}{R}\right)}^{2}}
Given: h=2Rh = 2R
∴g′=g1(1+2)2∴ {g}^{'} = g\dfrac{1}{{\left(1 + 2\right)}^{2}}
or g′=g9{g}^{'} = \dfrac{g}{9}
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