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JEE Main 202116 MarchEvening Shift
Exam
JEE Main
Year
2021
Date
16 March
Shift
Evening Shift
Subject
Physics
Chapter
Gravitation

JEE Main 2021 · 16 March · Evening Shift · Physics · Gravitation

If one wants to remove all the mass of the earth to infinity in...

If one wants to remove all the mass of the earth to infinity in order to break it up completely. The amount of energy that needs to be supplied will be x5GM2R\dfrac{x}{5}\dfrac{G{M}^{2}}{R} where xx is ________.

(Round off to the Nearest Integer)

(MM is the mass of earth, RR is the radius of earth, GG is the gravitational constant)

Correct answer

0

Step-by-step solution

Energy given =Uf−Ui= {U}_{f} - {U}_{i}

=0−(−35GM2R)= 0 - \left(- \dfrac{3}{5}\dfrac{G{M}^{2}}{R}\right)

=35GM2R= \dfrac{3}{5}\dfrac{G{M}^{2}}{R}

x=3x = 3

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