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JEE Main 202125 FebruaryEvening Shift
Exam
JEE Main
Year
2021
Date
25 February
Shift
Evening Shift
Subject
Physics
Chapter
Gravitation

JEE Main 2021 · 25 February · Evening Shift · Physics · Gravitation

The initial velocity v _ i required to project a body vertically...

The initial velocity vi{v}_{i} required to project a body vertically upward from the surface of the earth to reach a height of 10R10R, where RR is the radius of the earth, may be described in terms of escape velocity ve{v}_{e} such that vi=xy×ve{v}_{i} = \sqrt{\dfrac{x}{y}} \times {v}_{e}. The value of xx will be

Correct answer

0

Step-by-step solution

−GMm11R=−GMmR+12mv2\dfrac{- GMm}{11R} = \dfrac{- GMm}{R} + \dfrac{1}{2}m{v}^{2}

⇒v=20GM11R⇒ v = \sqrt{\dfrac{20GM}{11R}}

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