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JEE Main 20202 SeptemberMorning Shift
Exam
JEE Main
Year
2020
Date
2 September
Shift
Morning Shift
Subject
Physics
Chapter
Gravitation

JEE Main 2020 · 2 September · Morning Shift · Physics · Gravitation

The mass density of a spherical galaxy varies as (K)/(r) over a...

The mass density of a spherical galaxy varies as Kr\dfrac{K}{r} over a large distance rr from its center. In that region, a small star is in a circular orbit of radius RR. Then the period of revolution,TT depends on RR as:The mass density of a spherical galaxy varies as (K)/(r) over a large distance r from its center. In that region, a

Options

  1. AT2∝R{T}^{2} ∝ R
  2. BT2∝R3{T}^{2} ∝ {R}^{3}
  3. CT2∝1R3{T}^{2} ∝ \dfrac{1}{{R}^{3}}
  4. DT∝RT ∝ R

Correct answer

A. T2∝R{T}^{2} ∝ R

Step-by-step solution

M=∫ρdVM = ∫ ρdV

M=∫0Rkr4πr2drM = {∫}_{0}^{R}\dfrac{k}{r}4\pi{r}^{2}dr

M=4\pik∫0RrdrM = 4\pik{∫}_{0}^{R}rdr

M=4\pikR22=2\pikR2M = \dfrac{4\pik{R}^{2}}{2} = 2\pik{R}^{2}

The mass density of a spherical galaxy varies as (K)/(r) over a large distance r from its center. In that region, a

FG=GMmR2=mω02R{F}_{G} = \dfrac{GMm}{{R}^{2}} = m{\omega}_{0}^{2}R

⇒G4\pikR22R2=ω02R⇒ω0=2\pikGR⇒ \dfrac{G\dfrac{4\pik{R}^{2}}{2}}{{R}^{2}} = {\omega}_{0}^{2}R ⇒ {\omega}_{0} = \sqrt{\dfrac{2\pikG}{R}}

∵T=2πω0=2πR2\pikG=2\piRkG∵ T = \dfrac{2\pi}{{\omega}_{0}} = \dfrac{2\pi\sqrt{R}}{\sqrt{2\pikG}} = \sqrt{\dfrac{2\piR}{kG}}

⇒T2∝R⇒ {T}^{2} ∝ R

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