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JEE Main201910 Apr 2019Evening ShiftPhysicsGravitationActual

A spaceship orbits around a planet at a height of 20 k m from its surface. Assuming that only gravitational field of the planet acts on the spaceship, what will be the number of complete revolutions made by the spaceship in 24 hours around the planet? [Given: Mass of planet = 8 × 10 22 k g , Radius of planet = 2 × 10 6 m , Gravitational constant G = 6.67 × 10 - 11 N m 2 / k g 2 ]

Options

  1. A17
  2. B9
  3. C13
  4. D11

Correct answer

D. 11

Step-by-step solution

T = 2 π ( R + h ) 3 G M = 2 π 8.242 × 10 18 6.67 × 10 - 11 × 8 × 10 22 T ≈ 7809 s e c Number of revolutions in 24 hours: n = 86400 7809 = 11.06 ≈ 11 revolutions

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