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JEE Main201910 Jan 2019Morning ShiftPhysicsGravitationActual

A satellite is moving with a constant speed v in circular orbit around the earth. An object of mass ' m ' is ejected from the satellite such that it just escapes from the gravitational pull of the earth. At the time of ejection, the kinetic energy of the object is:

Options

  1. A3 2 m v 2
  2. Bm v 2
  3. C1 2 m v 2
  4. D2 m v 2

Correct answer

B. m v 2

Step-by-step solution

At height r from the centre of the Earth, orbital velocity is given as: o r b i t a l   v e l o c i t y   =   G M r V e = 2 v K . E = 1 2 m 2 v 2 = m v 2

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