If n is the number density and d is the diameter of the molecule,...

\mathrm{n}

is the number density and

\mathrm{d}

is the diameter of the molecule, then the average distance covered by a molecule between two successive collisions (i.e. mean free path) is represented by :

Options

A $\sqrt{2} \mathrm{n} \pi \mathrm{d}^2$
B $\frac{1}{\sqrt{2 n \pi d^2}}$
C $\frac{1}{\sqrt{2} n \pi d^2}$
D $\frac{1}{\sqrt{2} n^2 \pi^2 d^2}$

Correct answer

C. $\frac{1}{\sqrt{2} n \pi d^2}$

Step-by-step solution

\mathrm{n}=

number of molecule per unit volume

\mathrm{d}=

diameter of the molecule

\lambda=\frac{1}{\sqrt{2} \pi \mathrm{d}^2 \mathrm{n}}

(By Theory)

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