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A uniform heating wire of resistance 36   Ω is connected across a potential difference of 240     V . The wire is then cut into half and a potential difference of 240     V is applied across each half separately. The ratio of power dissipation in first case to the total power dissipation in the second case would be 1 :   x , where x is

Correct answer

4

Step-by-step solution

P = V 2 / R P 1 = V 2 R 2     ⇒    P 2 = V 2 R 2         ⇒    P 1 + P 2 = 4 V 2 R Now P 1 + P 2 P = 4 V 2 R V 2 R = 4

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