A mixture of hydrogen and oxygen has volume 500 cm 3 , temperature 300 K , pressure 400 k Pa and mass 0 . 76 g . The ratio of masses of oxygen to hydrogen will be:

Step-by-step solution

A number of moles of, O 2 = m 1 32 , the number of moles of, H 2 = m 2 2 . Using the ideal gas equation, P V = m 1 32 + m 2 2 25 3 × 300 , 400 × 10 3 × 500 × 10 - 6 = m 1 32 + m 2 2 25 × 100 ⇒ 2 × 10 2 = m 1 m 2 × 1 32 + 1 2 m 2 × 25 × 100 ⇒ 2 25 = m 1 m 2 × 1 32 + 1 2 m 2     . . . ( 1 ) ⇒ m 1 + m 2 = 0 . 76 ⇒ m 2 1 + m 1 m 2 = 76 100       . . . ( 2 ) ( 1 ) divided by ( 2 ) ; m 1 m 2 × 1 32 + 1 2 m 1 m 2 + 1 =