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JEE Main202126 Aug 2021Evening ShiftPhysicsKinetic Theory of GasesActual

A cylindrical container of volume 4 . 0 × 10 - 3 m 3 contains one mole of hydrogen and two moles of carbon dioxide. Assume the temperature of the mixture is 400 K . The pressure of the mixture of gases is : [Take gas constant as 8 . 3 J mol - 1 K - 1

Options

  1. A24 . 9 × 10 3   Pa
  2. B249 × 10 1   Pa
  3. C24 . 9 × 10 5   Pa
  4. D24 . 9   Pa

Correct answer

C. 24 . 9 × 10 5   Pa

Step-by-step solution

For gas A P A V = n A R T P A = ( 1 ) RT V for gas B P B V = n B RT P B = ( 2 ) R T V Now according to the Dalton's law of mixture, P = P A + P B = 3 R T V = 3 × 8 . 314 ( 400 ) 4 × 10 - 3 = 24 . 9 × 10 5   Pa

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