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JEE Main202126 Aug 2021Morning ShiftPhysicsKinetic Theory of GasesActual

The R.M.S. speeds of the molecules of Hydrogen, Oxygen, and Carbon dioxide at the same temperature are v H , v O and v C respectively, then:

Options

  1. Av C > v O > v H
  2. Bv H = v O > v C
  3. Cv H > v O > v C
  4. Dv H = v O = v C

Correct answer

C. v H > v O > v C

Step-by-step solution

The formula of root-mean-square speed in terms of absolute temperature and molecular mass of the gas is, v R M S = 3 R T M ⇒ v R M S ∝ 1 M , here we know that, M H 2 < M O 2 < M CO 2 ⇒ v H > v O > v C .

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