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JEE Main201912 Jan 2019Evening ShiftPhysicsKinetic Theory of GasesActual

An ideal gas is enclosed in a cylinder at pressure of 2 atm and temperature, 300 K . The mean time between two successive collisions is 6 × 10 - 8 s . If the pressure is doubled and temperature is increased to 500 K , the mean time between two successive collisions will be close to:

Options

  1. A2 x 10 - 7 s
  2. B3 x 10 - 6 s
  3. C0 . 5 x 10 - 8 s
  4. D4 x 10 - 8 s

Correct answer

D. 4 x 10 - 8 s

Step-by-step solution

τ = 1 2 n π d 2 v a v g Where n = number of molecules per unit volume. τ ∝ V T ⇒ τ ∝ T P τ 2 τ 1 = T 2 T 1 . P 1 P 2 ⇒ τ 2 = 6 × 10 - 8 × 5000 300 × 2 4 ≈ 4 × 10 - 8 s

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