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JEE Main 201912 JanuaryMorning Shift
Exam
JEE Main
Year
2019
Date
12 January
Shift
Morning Shift
Subject
Physics
Chapter
Kinetic Theory of Gases

JEE Main 2019 · 12 January · Morning Shift · Physics · Kinetic Theory of Gases

An ideal gas occupies a volume of 2 m ^ 3 at a pressure of 3 × 10 ^...

An ideal gas occupies a volume of 2m32{m}^{3} at a pressure of 3×106Pa.3 \times {10}^{6}Pa . The energy of the gas is:

Options

  1. A108J{10}^{8}J
  2. B9×106J9 \times {10}^{6}J
  3. C3×102J3 \times {10}^{2}J
  4. D6×104J6 \times {10}^{4}J

Correct answer

B. 9×106J9 \times {10}^{6}J

Step-by-step solution

V=2m3V = 2{m}^{3}

P=3×106PaP = 3 \times {10}^{6}Pa

PV=nRTPV = nRT

E=f2nRT=f2PV=32×3×106×2E = \dfrac{f}{2}nRT = \dfrac{f}{2}PV = \dfrac{3}{2} \times 3 \times {10}^{6} \times 2

=9×106J= 9 \times {10}^{6}J
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