A 15 g mass of nitrogen gas is enclosed in a vessel at a temperature, 27 o C . The amount of heat transferred to the gas, so that R . M . S . velocity of molecules is doubled, is about. R = 8 .3 J K mole - 1

Step-by-step solution

The formula of root-mean-square speed, v r m s = 3 R T M . For doubling the v r m s , temperature, should be made 4 -time is, T f = 273 + 27 × 4   K = 1200   K , the formula of, ∆ Q = ∆ U + W W = 0 , ⇒ ∆ Q = ∆ U = n C V   ∆ T = 15 28 × 5 2 R   ∆ T ⇒ ∆ Q = 15 28 × 5 2 × 8.3 × 1200 - 300   J ≈ 10   KJ .