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JEE Main 20199 JanuaryEvening Shift
Exam
JEE Main
Year
2019
Date
9 January
Shift
Evening Shift
Subject
Physics
Chapter
Kinetic Theory of Gases

JEE Main 2019 · 9 January · Evening Shift · Physics · Kinetic Theory of Gases

A 15g mass of nitrogen gas is enclosed in a vessel at a...

A 15g15g mass of nitrogen gas is enclosed in a vessel at a temperature, 27oC{27}^{o}C. The amount of heat transferred to the gas, so that R.M.S.R . M . S . velocity of molecules is doubled, is about.
\left[R = 8 .3 J{\left(Kmole\right)}^{- 1}\right]

Options

  1. A14kJ14kJ
  2. B10kJ10kJ
  3. C6kJ6kJ
  4. D0.9kJ0 .9 kJ

Correct answer

B. 10kJ10kJ

Step-by-step solution

The formula of root-mean-square speed, vrms=3RTM{v}_{rms} = \sqrt{\dfrac{3RT}{M}}. For doubling the vrms,{v}_{rms}, temperature, should be made 44-time is, Tf=(273+27)×4K=1200K{T}_{f} = \left(273 + 27\right)\times4K = 1200K, the formula of, ∆Q=∆U+W(W=0)∆ Q = ∆ U + W\left(W = 0\right),
⇒∆Q=∆U=nCV∆T=1528×52⇒ ∆ Q = ∆ U= n{C}_{V} ∆ T= \dfrac{15}{28} \times \dfrac{5}{2} R ∆ T<br/><br />⇒ ∆ Q = 1528×52×8.3×(1200−300)\dfrac{15}{28} \times \dfrac{5}{2} \times8.3 \times \left(1200 - 300\right) J\approx10KJ.</p></blockquote></p></blockquote>

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