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JEE Main 20199 JanuaryMorning Shift
Exam
JEE Main
Year
2019
Date
9 January
Shift
Morning Shift
Subject
Physics
Chapter
Kinetic Theory of Gases

JEE Main 2019 · 9 January · Morning Shift · Physics · Kinetic Theory of Gases

A mixture of 2 moles of helium gas (atomic mass = 4u) , and 1 mole...

A mixture of 2 moles of helium gas (atomic mass = 4u) , and 1 mole of argon gas (atomic mass = 40 u) is kept at 300K300K in a container. The ratio of their rms speeds \left[\dfrac{{V}_{rms}\left(helium\right)}{{V}_{rms} ( argon )}\right], is close to:

Options

  1. A0.450.45
  2. B2.242.24
  3. C0.320.32
  4. D3.163.16

Correct answer

D. 3.163.16

Step-by-step solution

VRMS=3RTM{V}_{RMS} = \sqrt{\dfrac{3RT}{M}}

∴(VRMS)He(VRMS)Ar=MArMHe=404=10=3.16∴ \dfrac{{( {V}_{RMS} )}_{He}}{{( {V}_{RMS} )}_{Ar}} = \sqrt{\dfrac{{M}_{Ar}}{{M}_{He}}} = \sqrt{\dfrac{40}{4}} = \sqrt{10} = 3.16
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