JEE Main202628 January 2026Evening ShiftPhysicsLaws of MotionActual
A small block of mass m slides down from the top of a frictionless inclined surface, while the inclined plane is moving towards left with constant acceleration a₀ . The angle between the inclined plane and ground is and its base length is L . Assuming that initially the small block is at the top of the inclined plane, the time it takes to reach the lowest point of the inclined plane is _ _ _ _ .
Options
- A2 L g -a₀
- B4 L g ² -a₀
- C2 L g 2 -a₀(1+ 2 )
- D4 L g 2 -a₀(1+ 2 )
Correct answer
D. 4 L g 2 -a₀(1+ 2 )
Step-by-step solution
mg - ma₀ = ma a = g - a₀ Now using, S = ut + 1 2 a_ down t^2 L = 1 2 (g - a₀ )t^2 t = 2L g - a₀ ^2 t = 4L g 2 - a₀(1 + 2 )