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JEE Main 202628 JanuaryMorning Shift
Exam
JEE Main
Year
2026
Date
28 January
Shift
Morning Shift
Subject
Physics
Chapter
Laws of Motion

JEE Main 2026 · 28 January · Morning Shift · Physics · Laws of Motion

A particle of mass m falls from rest through a resistive medium...

A particle of mass mm falls from rest through a resistive medium having resistive force, F=−kvF=-k v, where vv is the velocity of the particle and kk is a constant. Which of the following graphs represents velocity (vv) versus time (tt)?A particle of mass m falls from rest through a resistive medium having resistive force, F=-k v , where v is theA particle of mass m falls from rest through a resistive medium having resistive force, F=-k v , where v is theA particle of mass m falls from rest through a resistive medium having resistive force, F=-k v , where v is theA particle of mass m falls from rest through a resistive medium having resistive force, F=-k v , where v is the

Options

  1. AA body projected vertically upwards with a certain speed from the top of a tower reaches the ground in t_1 . If it is
  2. BA body projected vertically upwards with a certain speed from the top of a tower reaches the ground in t_1 . If it is
  3. CA body projected vertically upwards with a certain speed from the top of a tower reaches the ground in t_1 . If it is
  4. DA body projected vertically upwards with a certain speed from the top of a tower reaches the ground in t_1 . If it is

Correct answer

A. A body projected vertically upwards with a certain speed from the top of a tower reaches the ground in t_1 . If it is

Step-by-step solution

The particle experiences downward gravitational force (mg) and upward resistive force (-kv).
The equation of motion is mdvdt=mg−kvm\frac{dv}{dt} = mg - kv.
Initially at t=0t=0, v=0v=0 gives maximum acceleration a0=ga_0 = g.
As velocity increases, the resistive force increases, reducing the net acceleration.
Eventually the particle reaches terminal velocity vt=mgkv_t = \frac{mg}{k} when acceleration becomes zero.
The velocity-time graph shows an increasing curve starting from origin with decreasing slope, asymptotically approaching the terminal velocity.
This behavior matches option (1), which displays a curve starting at (0,0) with steep initial slope that gradually flattens.
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